Swift Set insert method replaces the element if it was already in the set.
Originator: | simonracz | ||
Number: | rdar://24101520 | Date Originated: | 08-Jan-2016 |
Status: | Open | Resolved: | closed |
Product: | iOS SDK | Product Version: | |
Classification: | Reproducible: | always |
Summary: Unlike NSMutableSet's addObject: method, Swift's Set's insert method replaces the element if it was already in the set. Steps to Reproduce: // Can be copied to a Playground class Foo: Hashable, CustomStringConvertible { let value: Int let notPartOfValue: Int init(value: Int, notPartOfValue: Int) { self.value = value self.notPartOfValue = notPartOfValue } var hashValue: Int { return value.hashValue } var description: String { return "{Foo, v:\(value), n:\(notPartOfValue)}" } } func ==(lhs: Foo, rhs: Foo) -> Bool { return lhs.value == rhs.value } var s = Set<Foo>() s.insert(Foo(value: 1, notPartOfValue: 100)) print(s) s.insert(Foo(value: 1, notPartOfValue: 200)) print(s) Expected Results: Last line should print : "[{Foo, v:1, n:100}]\n" Actual Results: Last line prints "[{Foo, v:1, n:200}]\n" Version: Latest public xcode 7, Swift 2 Notes: http://www.chaonis.com/2016/01/swift-set-vs-nsmutableset/ Configuration: It doesn't matter Attachments:
Comments
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It's fixed in Swift 4.