Foundation's range(of:options:) doesn't support Swift 4's Substring type
Originator: | jp | ||
Number: | rdar://33838766 | Date Originated: | 10-Aug-2017 04:33 PM |
Status: | Open | Resolved: | |
Product: | Developer Tools | Product Version: | Xcode 9 beta 5 (9M202q) |
Classification: | Serious Bug | Reproducible: | Always |
Summary: Foundation's range(of:options:) doesn't support Swift 4's Substring type. The range returned is calculated in the original string, not the substring. Steps to Reproduce: Run the following code on macOS (in a Playground or via the command line): ```swift import Foundation let str = "Yo Hello, playground" let start = str.index(str.startIndex, offsetBy: 3) let substr = str[start...] if let commaSpaceEnd = substr.range(of: ", ", options: .backwards)?.upperBound { print(substr[commaSpaceEnd...]) } if let commaSpaceEnd = str.range(of: ", ", options: .backwards)?.upperBound { print(str[commaSpaceEnd...]) } ``` Expected Results: Should print: playground playground Actual Results: Actually prints: o, playground playground Version: Xcode 9 beta 5 (9M202q) Notes:
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